Answer:
0.25
Explanation:
The coefficient of the friction between the box and the surface can be calculated by using the formula:
[tex]{ \boxed{ \sf{\mu = \dfrac{F_k}{N}}}}[/tex]
where :
- [tex]\mu [/tex] is coefficient of friction
- [tex] \sf F_k[/tex] is Kinetic force, i.e 50 N
- N is normal force.
Normal force can be calculated by using the formula :
[tex] \sf F_n = mg [/tex]
where:
- m is mass of the body,
- the value of g is 10 m/s²
Substitute the given values
[tex] \sf F_n = 20 kg \times 10 m/s^2 [/tex]
[tex]\sf F_n = 200 \ N [/tex]
Now Let's calculate the coefficient of friction between the box and the surface,
[tex]{ \sf\mu = \dfrac{F_k}{N}}[/tex]
substitute the values
[tex]{ \sf\mu = \dfrac{50 \ N }{200 \ N }}[/tex]
[tex]{\boxed{ \bf{\mu =0.25}}}[/tex]
Therefore, the coefficient of the friction between the box and the surface is 0.25
