Answer: 0.887 g
Explanation:
To calculate the amount of oxygen produced by the decomposition of 12 grams of mercury (II) oxide, we first need to balance the chemical equation for the reaction. The balanced equation is:
2HgO→2Hg+O2
2HgO→2Hg+O2
This means that for every 2 moles of mercury (II) oxide decomposed, 1 mole of oxygen gas is produced. The molar mass of mercury (II) oxide is 216.59 g/mol, which means that 12 grams of mercury (II) oxide is equivalent to:
12 g216.59 g/mol=0.0554 mol
216.59 g/mol12 g=0.0554 mol
Therefore, the amount of oxygen produced by the decomposition of 12 grams of mercury (II) oxide is:
0.0554 mol2×32 g/mol= 0.887 g
