A photon has a frequency of 8.63×10⁸ Hz. What is the energy of this photon? (h=6.626×10⁻³⁴ J*s)

A. 5.71×10⁻²⁵ J
B. 5.71×10⁻²⁶ J
C. 5.71×10⁻²⁷ J
D. 5.71×10⁻²⁸ J

Respuesta :

Answer:

A. 5.71 × 10⁻²⁵ J

Explanation:

Energy of the photon can be calculated by using the formula:

[tex] \ \: E = h \nu [/tex]

where :

  • h is planck's constant (h = 6.626 × 10⁻³⁴ J*s)
  • [tex]\nu [/tex] is frequency.

We have frequency = 8.63 × 10⁸ Hz.

substitute the values in the formula

[tex]E = 6.626 \times 10^{-34} Js \times 8.63 \times 10^8 Hz[/tex]

[tex]E = 57.1 \times 10^{-26}[/tex]

[tex]E = 5.71 \times 10^{-25} J[/tex]

Hence, the energy of the photon is A. 5.71 × 10⁻²⁵ J

Final answer:

The energy of a photon with a frequency of 8.63×10⁸ Hz is calculated using the equation E = hf. Using Planck's constant, the energy is found to be 5.71×10⁻²⁵ J, corresponding to option A.

Explanation:

To calculate the energy of a photon with a given frequency, we use the equation E = hf, where E is the energy, h is Planck's constant, and f is the frequency of the photon.

Given the frequency of the photon as 8.63×10⁸ Hz and Planck's constant as 6.626×10⁻³⁴ J*s, we can calculate the energy of the photon as follows: E = (6.626×10⁻³⁴ J*s) × (8.63×10⁸ Hz) = 5.71×10⁻²⁵ J

Therefore, the correct answer for the energy of the photon is 5.71×10⁻²⁵ J, which corresponds to option A.