At closest approach, the 722 kg voyager 2 probe flew by Neptune at an altitude of 29,240,000 meters. What was the probes weight at that moments of Neptune has a radius of 24,900,000 meters and a mass of 9.99 x 10^25 kg?

Respuesta :

Explanation:

To calculate the weight of the Voyager 2 probe at its closest approach to Neptune, you can use the gravitational force formula:

\[ F = \frac{G \cdot m_1 \cdot m_2}{r^2} \]

where:

- \( F \) is the gravitational force,

- \( G \) is the gravitational constant (\(6.674 \times 10^{-11} \, \text{Nm}^2/\text{kg}^2\)),

- \( m_1 \) and \( m_2 \) are the masses of the two objects (probe and Neptune),

- \( r \) is the separation distance between the centers of the two masses.

The weight (\( W \)) of the probe is related to the gravitational force by \( W = m \cdot g \), where \( g \) is the acceleration due to gravity.

Let's denote:

- \( m \) as the mass of the Voyager 2 probe (722 kg),

- \( r \) as the separation distance (altitude) between the probe and Neptune (29,240,000 m + Neptune's radius).

Now, calculate \( r \) and use the formulas to find the weight of the Voyager 2 probe at that moment. Make sure to convert all units to meters and kilograms for consistency.

\[ r = 29,240,000 \, \text{m} + 24,900,000 \, \text{m} \]

\[ r^2 = r \cdot r \]

\[ F = \frac{G \cdot m_{\text{probe}} \cdot m_{\text{Neptune}}}{r^2} \]

\[ W = m_{\text{probe}} \cdot g \]

Plug in the values and calculate the result. Note: \( g \) is the acceleration due to gravity on Neptune, which can be calculated using the same formula \( g = \frac{G \cdot m_{\text{Neptune}}}{r_{\text{Neptune}}^2} \).