Answer:
Explanation:
(a) Type of Reaction Depicted on Scheme Q3
The type of reaction depicted on Scheme Q3 is an elimination reaction. This can be inferred from the presence of a strong base (NaOH) and the formation of a double bond in the product. Elimination reactions involve the removal of atoms or groups from a molecule to form a double bond or triple bond.
(b) Mechanism Responsible for the Formation of I
The mechanism responsible for the formation of I in Scheme Q3 is the E2 (bimolecular elimination) mechanism. In the E2 mechanism, the base (NaOH) abstracts a proton from the beta carbon, while the leaving group (H-) leaves simultaneously, resulting in the formation of a double bond. This mechanism occurs in one step and involves the concerted movement of electrons.
(c) Most Thermodynamically Stable Compound between II and III
To determine which compound between II and III is the most thermodynamically stable, we need more information or a comparison of their structures. Unfortunately, the provided image does not include the structures of II and III. Therefore, it is not possible to determine the relative thermodynamic stability of these compounds.
(d) Product of the Ozonolysis of III and IUPAC Naming
The product of the ozonolysis of compound III (Figure Q3c) in the presence of H₂O₂ is not provided in the image. Without the structure of compound III, it is not possible to draw the product or provide its IUPAC name.
Please provide additional information or a complete image to assist further with part (d) of the question.