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8g of sulfur is burned in a bottle containing 4.48L of oxygen.

A. Write the reaction equation.

B. Find the mass of sulfur involved in the reaction.

C. Calculate the mass of sulfur remaining after combustion. It is known that oxygen

32g has a mass of 22.4L

Let (S = 32, 0 = 16) * g / m * ol

Respuesta :

TopZ

Answer: A. The reaction equation for the combustion of sulfur can be written as:

2S + 3O2 -> 2SO3

B. To find the mass of sulfur involved in the reaction, we need to calculate the moles of sulfur.

Molar mass of sulfur (S) = 32 g/mol

Moles of sulfur = Mass of sulfur / Molar mass of sulfur

Moles of sulfur = 8 g / 32 g/mol

Moles of sulfur = 0.25 mol

C. To calculate the mass of sulfur remaining after combustion, we need to determine the limiting reactant between sulfur and oxygen.

First, let's calculate the moles of oxygen available:

Given that 1 mol of oxygen occupies 22.4 L, we can use the volume of oxygen given to calculate the moles.

Moles of oxygen = Volume of oxygen / Molar volume of oxygen

Moles of oxygen = 4.48 L / 22.4 L/mol

Moles of oxygen = 0.20 mol

From the balanced equation, we can see that the stoichiometric ratio between sulfur and oxygen is 2:3.

Since the stoichiometric ratio of sulfur to oxygen is 2:3, we can calculate the moles of sulfur dioxide (product) produced using the moles of sulfur consumed.

Moles of sulfur dioxide = Moles of sulfur * (2 moles of SO3 / 2 moles of S)

Moles of sulfur dioxide = 0.25 mol * (2 mol SO3 / 2 mol S)

Moles of sulfur dioxide = 0.25 mol

Based on the stoichiometry, the same number of moles of sulfur dioxide is consumed as moles of sulfur.

Therefore, all the sulfur is consumed during the reaction, resulting in no sulfur remaining after combustion.

The mass of sulfur remaining after combustion is 0 g.

Meherpuya

Answer:

A. The balanced reaction equation for the combustion of sulfur (S) with oxygen (O2) is:

\[ 2S + 3O_2 \rightarrow 2SO_3 \]

B. To find the mass of sulfur involved, you need to use stoichiometry. The molar mass of sulfur (S) is 32 g/mol. So, for 8g of sulfur:

\[ \text{Moles of S} = \frac{8 \text{ g}}{32 \text{ g/mol}} \]

C. To calculate the mass of sulfur remaining after combustion, you need to compare the moles of sulfur and oxygen in the balanced equation. The molar mass of oxygen (O2) is 32 g/mol.

\[ \text{Moles of O}_2 = \frac{4.48 \text{ L}}{22.4 \text{ L/mol}} \]

Compare the moles of S and O2 to determine the limiting reactant, then use that information to find the remaining mass of sulfur.

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