Answer:
x = 2[tex]\sqrt{2}[/tex]
Step-by-step explanation:
given the triangle is isosceles , then
the 2 legs are congruent ( equal ), both x
Using Pythagoras' identity in the right triangle
a² + b² = c²
c is the hypotenuse and a, b the legs
x² + x² = 4²
2x² = 16 ( divide both sides by 2 )
x² = 8 ( take square root of both sides )
[tex]\sqrt{x^2}[/tex] = [tex]\sqrt{8}[/tex] , that is
x = [tex]\sqrt{4(2)}[/tex] = [tex]\sqrt{4}[/tex] × [tex]\sqrt{2}[/tex] = 2[tex]\sqrt{2}[/tex]
