3. Kay -anna and Amari are making gift bags for Kay-anna's cousin's birthday party. Each bag will have
4 pieces of candy and two small toys. Kay-anna went to the store with $20 to buy the candy. She
found bags that cost $3.79 and have 26 pieces of candy in each. Amari had the job of buying the toys,
and at the store she found packets of 15 toys that cost $6.99 each. She has a budget of $25. If Kay-
anna and Amari buy as much as each can afford, how many gift bags can they make?

Question

13-01-2024
Mathematics

contestada

3. Kay -anna and Amari are making gift bags for Kay-anna's cousin's birthday party. Each bag will have
4 pieces of candy and two small toys. Kay-anna went to the store with $20 to buy the candy. She
found bags that cost $3.79 and have 26 pieces of candy in each. Amari had the job of buying the toys,
and at the store she found packets of 15 toys that cost $6.99 each. She has a budget of $25. If Kay-
anna and Amari buy as much as each can afford, how many gift bags can they make?

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Meherpuya Meherpuya · Answer 1 · 2024-01-13T16:21:11+01:00

Answer:

First, let's find out how many bags of candy Kay-anna can buy. She has $20 and each bag costs $3.79, so the number of bags she can buy is approximately $20 / $3.79 = 5.28 bags. Since you can't have a fraction of a bag, she can buy 5 bags.

Now, let's find out how many bags of toys Amari can buy. She has a budget of $25, and each packet of toys costs $6.99, so the number of packets she can buy is approximately $25 / $6.99 = 3.58 packets. Again, since you can't have a fraction of a packet, she can buy 3 packets.

Since each bag requires 4 pieces of candy and 2 small toys, and Kay-anna can make 5 bags with her candy, and Amari can make 3 bags with her toys, the limiting factor is 3 bags. Therefore, they can make 3 gift bags in total.