Respuesta :
Answer: a) 10.84 m/s
Explanation:
To calculate the velocity just before splashing into the water, we can apply the principle behind the law of conservation of energy, which states that energy cannot be created nor destroyed.
This means that the total gravitational potential energy is equal to the total kinetic energy.
The formula for gravitational potential energy is given as:
U = mgh, where:
- U represents gravitational potential energy
- m represents the mass
- g represents the acceleration due to gravity
- h represents the height at which the object is held above the surface
The formula for kinetic energy is given as:
K = 0.5mv², where:
- K represents kinetic energy
- m represents the mass
- v represents velocity
According to the law of conservation of energy, we can set these equations equal to each other, since the total gravitational potential energy must be equal to the total kinetic energy.
mgh = 0.5mv²
We can simplify this equation further by canceling out the m's, meaning that mass is irrelevant in calculating the final velocity.
gh = 0.5v²
Plugging in our given values for h = 6m and g = 9.81m/s²:
(9.81)(6) = 0.5v²
Now, let's solve for v:
v² = [tex]\frac{(9.81)(6)}{0.5}[/tex]
v.= [tex]\sqrt{\frac{(9.81)(6)}{0.5}}[/tex]
v.= 10.84
Therefore, the velocity just before splashing in the water is 10.84 m/s.
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