Respuesta :

irspow
By similar triangles we know:

h1/x1=h2/x2

p/37=33/83  multiply both sides by 37

p=1221/83 m

p≈14.71 m (to nearest hundredth of a centimeter)

Answer:

The height of the telephone pole is 14.711 m (Approx) .

Step-by-step explanation:

Let us assume that the height be x .

Let us assume that the shadow  be y .

(As the shadow is always proportional to the height .)

Thus

[tex]x\propto y[/tex]

y = kx

Where k is the constant of proportionality .

As given

if a statue that is 33 cm tall cast a shadow 83 cm long .

y = 83 cm

x = 33 cm

Put in the equation y = kx .

83 = 33k

[tex]k = \frac{83}{33}[/tex]

As given

A telephone pole cast a shadow that is 37 m .

Let us assume that the height of the telephone pole be z .

As

1m = 100cm

37m = 3700 cm

y = 3700 cm

x = z

Put in the equation  y = kx .

3700 = zk

[tex]k = \frac{3700}{z}[/tex]

Compare the value of k .

[tex]\frac{3700}{z} = \frac{83}{33}[/tex]

[tex]\frac{3700\times 33}{83} =z[/tex]

[tex]\frac{122100}{83} =z[/tex]

z = 1471.1 cm(Approx)

As

[tex]1\ cm = \frac{1}{100}\ m[/tex]

[tex]1471.1\ cm = \frac{1471.1}{100}\ m[/tex]

                       = 14.711 m (Approx)

Therefore the  height of the telephone pole is 14.711 m (Approx) .