Respuesta :
By similar triangles we know:
h1/x1=h2/x2
p/37=33/83 multiply both sides by 37
p=1221/83 m
p≈14.71 m (to nearest hundredth of a centimeter)
h1/x1=h2/x2
p/37=33/83 multiply both sides by 37
p=1221/83 m
p≈14.71 m (to nearest hundredth of a centimeter)
Answer:
The height of the telephone pole is 14.711 m (Approx) .
Step-by-step explanation:
Let us assume that the height be x .
Let us assume that the shadow be y .
(As the shadow is always proportional to the height .)
Thus
[tex]x\propto y[/tex]
y = kx
Where k is the constant of proportionality .
As given
if a statue that is 33 cm tall cast a shadow 83 cm long .
y = 83 cm
x = 33 cm
Put in the equation y = kx .
83 = 33k
[tex]k = \frac{83}{33}[/tex]
As given
A telephone pole cast a shadow that is 37 m .
Let us assume that the height of the telephone pole be z .
As
1m = 100cm
37m = 3700 cm
y = 3700 cm
x = z
Put in the equation y = kx .
3700 = zk
[tex]k = \frac{3700}{z}[/tex]
Compare the value of k .
[tex]\frac{3700}{z} = \frac{83}{33}[/tex]
[tex]\frac{3700\times 33}{83} =z[/tex]
[tex]\frac{122100}{83} =z[/tex]
z = 1471.1 cm(Approx)
As
[tex]1\ cm = \frac{1}{100}\ m[/tex]
[tex]1471.1\ cm = \frac{1471.1}{100}\ m[/tex]
= 14.711 m (Approx)
Therefore the height of the telephone pole is 14.711 m (Approx) .