Respuesta :
Given that one die is a 6. So for the sum of the dice to be less than or equal to 8, the other die must be equal to or less than 2.
And the probability of roll a two or less is:
P(≤2)=2/6=1/3
And the probability of roll a two or less is:
P(≤2)=2/6=1/3
[tex]|\Omega|=6^2=36\\
|A|=4\\\\
P(A)=\dfrac{4}{36}=\dfrac{1}{9}\approx11\%[/tex]