A bowling ball weighs 7.26 kg and takes 3.64 seconds to travel the 19.2 m length of the bowling alley. assuming the velocity is constant, what is the kinetic energy of the bowling ball?

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TammyP
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The kinetic energy of the bowling ball is 100.81 J.

Given data:

The mass of bowling ball is, m = 7.26 kg.

The time interval is, t = 3.64 s.

The length of path covered is, L = 19.2 m.

First obtain the speed of ball from the given equation,

[tex]v = \dfrac{L}{t}[/tex]

Here, v is the speed of ball.

Solving as,

[tex]v = \dfrac{19.2}{3.64}\\\\v=5.27 \;\rm m/s[/tex]

Now, the expression for the kinetic energy is,

[tex]KE = \dfrac{1}{2}mv^{2}[/tex]

Solve by substituting the values as,

[tex]KE = \dfrac{1}{2} \times 7.26 \times 5.27^{2}\\\\KE=100.81 \;\rm J[/tex]

Thus, we can conclude that the kinetic energy of the bowling ball is 100.81 J.

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