Write the ions present in a solution of k3po4. express your answers as chemical formulas separated by a comma. offset subscripts and charges on each ion.

Respuesta :

K₃PO₄ → 3K⁺ + PO₄³⁻

PO₄³⁻ + H₂O ⇄ HPO₄²⁻ + OH⁻

HPO₄²⁻ + H₂O ⇄ H₂PO₄⁻ + OH⁻

H₂PO₄⁻ + H₂O ⇄ H₃PO₄ + OH⁻

K⁺, PO₄³⁻, HPO₄²⁻, H₂PO₄⁻, OH⁻

The species formed by the dissolution of [tex]\rm K_3PO_4[/tex], with water will result in the formation of [tex]\rm K^+\;,\,PO_4^3^-\;,\;HPO_4^2^-\;,\;H_2PO_4^-\;and,\;OH^-[/tex].

In the solution of [tex]\rm K_3PO_4[/tex], there is the dissociation of compounds in the water.

The dissociation of [tex]\rm K_3PO_4[/tex] will lead to :

[tex]\rm K_3PO_4\;\rightarrow\;3\;K^+\;+\;PO_4^-^3[/tex]

The phosphate ions formed are further dissociated by reaction with the water molecule.

[tex]\rm PO_4^-^3\;+\;H_2O\;\rightarrow\;HPO_4^2^-\;+\;OH^-[/tex]

[tex]\rm HPO_4^2^-\;+\;H_2O\;\rightarrow\;H_2PO_4^-\;+\;OH^-[/tex]

The species formed by the reaction  of [tex]\rm K_3PO_4[/tex], with water will result in formation of [tex]\rm K^+\;,\,PO_4^3^-\;,\;HPO_4^2^-\;,\;H_2PO_4^-\;and,\;OH^-[/tex].

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