A fixed amount of gas occupies a volume of 7.25 l at a pressure of 4.52 atm. what will be the volume occupied if the pressure is decreased to 1.21 atm at constant temperature?

Respuesta :

P1V1=P2V2
SO
7.25X4.52=1.21XV2
V2=27.1 l

The volume occupied if the pressure is decreased to 1.21 atm at constant temperature is 27.08 L

Data obtained from the question

  • Initial volume (V₁) = 7.25 L
  • Initial pressure (P₁) = 4.52 atm
  • Temperature = Constant
  • New pressure (P₂) = 1.21 atm
  • New Volume (V₂) =?

How to determine the new volume

The new volume of the gas can be obtained by using the Boyle's law equation as illustrated below:

P₁V₁ = P₂V₂

4.52 × 7.25 = 1.21 × V₂

Divide both sides by 1.21

V₂ = (4.52 × 7.25) / 1.21

V₂ = 27.08 L

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