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The projectile motion of an object can be modeled using s(t) = gt2 + v0t + s0, where g is the acceleration due to gravity, t is the time in seconds since launch, s(t) is the height after t seconds, v0 is the initial velocity, and s0 is the initial height. The acceleration due to gravity is –4.9 m/s2. An object is launched at an initial velocity of 19.6 meters per second from an initial height of 24.5 meters. Which equation can be used to find the number of seconds it takes the object to hit the ground? 0 = –4.9t2 + 19.6t + 24.5 0 = –4.9t2 + 24.5t + 19.6 19.6 = –4.9t2 + 24.5t 24.5 = –4.9t2 + 19.6t

Respuesta :

So for projectile motion questions, we use the Cartesian equations.
Given that s(t) is the height of the projectile at an arbitrary time, t, we want the height of the projectile to equal to zero in order to find its flight time.

Let s(t) = 0.
[tex]gt^{2} + V_0 t + s_0 = 0[/tex]
Now, the initial velocity of the projectile is given to be 19.6, and the initial height is 24.5.

Substitute those in to find:
[tex]-4.9t^{2} + 19.6t + 24.5 = 0[/tex]
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Answer:

I think its A on edge

Step-by-step explanation:

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