Answer:
The enlarge height is 15 in .
Step-by-step explanation:
Let us assume that the width be w .
Let us assume that the height be h .
(As width and height of the photograph are proportional.)
[tex]w \propto h[/tex]
w = kh
Where k is the constant of proportionality .
As given
Iris has a family photograph with a width of 8 in and height of 10 in.
Here w = 8 in , h = 10 in
Put in the equation w = kh .
8 = 10k
[tex]k = \frac{8}{10}[/tex]
She wants to enlarge the photograph so that it's width is 12 in.
Let us assume that the enlarge height be x .
Here w = 12 in , h = x
Put in the equation w = kh .
12 = kx
[tex]k = \frac{12}{x}[/tex]
Compare the value of k .
[tex]\frac{8}{10} = \frac{12}{x}[/tex]
[tex]x= \frac{12\times 10}{8}[/tex]
[tex]x= \frac{120}{8}[/tex]
x = 15 in
Therefore the enlarge height is 15 in .
