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14-07-2017
Chemistry

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The gas in a cylinder has a volume of 5 liters at a pressure of 101 kPa. The pressure of the gas is increased to 202 kPa. Assuming the temperature remains constant, what would the new volume be? L

Respuesta :

Floki22 Floki22

14-07-2017

P1V1 = P2V2

P1 = 101 kPa
V1 = 5 l
P2 = 202 kPa
V2 = ?

101*5 = 202*V2

V2 = 505 / 202

V2 = 2,5 liters

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