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the half-life of sodium-22 is 2.6 years. A sample contains 800 mg of this isotope. Which expression represents the mass.od sodium remaining after h half-lives?

Respuesta :

just did this assignment. the correct answer is S = 800(0.5)h
the next answer is h=y/2.6
the one after that is S = 800(0.766)y
the last one is 85.2 mg
Eduard22sly

The expression that represents the mass of sodium remaining after h half-lives is S = 800(0.5)ʰ

Data obtained from the question

  • Half-life (t½) = 2.6 years.
  • Original amount (S₀) = 800 mg
  • Number of half-lives (n) = h
  • Amount remaining (S) = ?

How do we determine the amount remaining?

The amount remaining can be obtained as illustrated below

S = S₀ / 2ⁿ

S = S₀ × (1/2)ⁿ

S = S₀ × (0.5)ⁿ

S = 800 × (0.5)ʰ

S = 800(0.5)ʰ

Complete question

The half-life of sodium-22 is 2.6 years. A sample contains 800 mg of this isotope.

Which expression represents the mass of sodium remaining after h half-lives?

S = 0.5(800)^h

S = 800(0.5)^h

S = 8000.5^h

S = 800^h + 0.5

Which expression relates h, the number of half-lives, and y, the number of years?

Learn more about half life:

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