Respuesta :

Solve the second equation for y

x+2y = -8
x+2y-x = -8-x
2y = -x-8
2y/2 = -x/2 -8/2
y = (-1/2)x - 4

The slope here is -1/2, which is the same slope as the first equation. Because of this fact and the fact that the y intercept is not the same, we have two parallel lines. The parallel lines never cross. 

There are no solutions

The linear system have zero number of solutions.

What is System of equations ?

System of equations is a set of simultaneous equations, also known as a system of equations or an equation system, is a finite set of equations for which common solutions are sought.

We have,

[tex]y=-\frac{1}{2}x +4[/tex]     [tex].....(i)[/tex]

And [tex]x+2y=-8[/tex]     [tex].....(ii)[/tex]

Now,

Rewrite the first equation,

[tex]y=-\frac{1}{2}x +4[/tex]

[tex]2y=-x+8[/tex]

[tex]2y+x=8[/tex]     [tex].....(iii)[/tex]

So,

Now compare ratios of  equation  [tex](iii)[/tex] and [tex](ii)[/tex] and ,

i.e.

[tex]\frac{a_{1} }{a_{2} } ,\frac{b_{1} }{b_{2} } ,\frac{c_{1} }{c_{2} }[/tex]

So,

[tex]\frac{a_{1} }{a_{2} } =\frac{1}{1}=1[/tex],

[tex]\frac{b_{1} }{b_{2} } =\frac{2}{2}=1[/tex],

[tex]\frac{c_{1} }{c_{2} } =\frac{8}{-8}=-1[/tex],

From ratios it is clear that,

[tex]\frac{a_{1} }{a_{2} } =\frac{b_{1} }{b_{2} } \neq \frac{c_{1} }{c_{2} }[/tex]

This means that these equations are parallel and have no solution.

Hence, we can say that the linear system have zero number of solutions.

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