g(x)=4x^2-16
To shift to the right we have to subtract from the value of x, in this case by 5 units...
h(x)=4(x-5)^2-16
h(x)=4(x^2-10x+25)-16
h(x)=4x^2-40x+100-16
h(x)=4x^2-40x+84
Now to shift the function downwards by 2 units we must subtract the constant 2 from h(x)
h(x)=4x^2-40x+84-2
h(x)=4x^2-40x+82