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The solution to this system of equations lies between the x-values 0 and 2. Using up to three iterations of successive approximation, find an approximate x-value representing the solution to the system.

y = 4^x-1
y = (1/2)^x-2

The approximate solution to this system of equations is
A. 1.375
B. 1.875
C. 1.5

Respuesta :

Answer:

The approximate solution of the given system of equations is [tex]1.333[/tex].

Step-by-step explanation:

The given equations are

[tex]y=4^{x-1}[/tex]                       ..... (1)

[tex]y=(\frac{1}{2})^{x-2}[/tex]         .... (2)

Equate both functions to find the intersection point of both function.

[tex]4^{x-1}=(\frac{1}{2})^{x-2}[/tex]

[tex](2^2)^{x-1}=(2^{-1})^{x-2}[/tex]

Use [tex]a^{mn}=(a^m)^n[/tex] property of exponent.

[tex]2^{2x-2}=2^{-x+2}[/tex]

Since the base is same, therefore compare the exponents.

[tex]2x-2=-x+2[/tex]

[tex]3x=4[/tex]

[tex]x=\frac{4}{3}[/tex]

[tex]x=1.333[/tex]

Therefore the approximate solution is [tex]1.333[/tex].

Lanuel

An approximate x-value that represents the solution to the system of equations is equal to: C. 1.5.

How to find an approximate x-value?

Since the solution to this system of equations lies between the x-values (0 and 2), we would use the iterations of successive approximation to find an approximate x-value that represents the solution to the system of equations as follows:

y = y

4ˣ⁻¹ = 1/2ˣ⁻²

Applying the laws of power, we have:

2²⁽ˣ⁻¹⁾ = 1/2ˣ⁻²

2²ˣ⁻² = 2⁻ˣ⁺²

Evaluating the powers, we have:

2x - 2 = -x + 2

2x + x = 2 + 2

3x = 4

x = 4/3

x = 1.33.

The equation would only have a solution when the x-values lies between 0 and 2.

[tex]f(x) = 4^{x-1}\\\\f(1.33) = 4^{1.33-1}\\\\f(1.33) = 4^{0.33}[/tex]

f(1.33) = 1.58.

By using x = 1.4, we have:

[tex]f(x) = 4^{x-1}\\\\f(1.4) = 4^{1.4-1}\\\\f(1.4) = 4^{0.4}[/tex]

f(1.4) = 1.74.

By using x = 1.5, we have:

[tex]f(x) = 4^{x-1}\\\\f(1.5) = 4^{1.5-1}\\\\f(1.5) = 4^{0.5}[/tex]

f(1.5) = 2.

Read more on equations here: brainly.com/question/13170908

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