Respuesta :
pOH=4.22
pOH = -lg[OH⁻]
[OH⁻]=10^(-pOH)
[OH⁻]=10⁻⁴·²² = 6.0×10⁻⁵ mol/L
6.0×10⁻⁵ M
pOH = -lg[OH⁻]
[OH⁻]=10^(-pOH)
[OH⁻]=10⁻⁴·²² = 6.0×10⁻⁵ mol/L
6.0×10⁻⁵ M
Answer : The correct option is, [tex]6.0\times 10^{-5}M[/tex]
Explanation : Given,
pOH = 4.22
pOH : It is defined as the negative logarithm of hydroxide ion concentration.
Now we have to calculate the [tex]OH^-[/tex] concentration.
Formula used :
[tex]pOH=-\log [OH^-][/tex]
Now put all the given values in this formula, we get the concentration of hydroxide ion.
[tex]4.22=-\log [OH^-][/tex]
[tex][OH^-]=6.0\times 10^{-5}M[/tex]
Therefore, the [tex]OH^-[/tex] concentration is, [tex]6.0\times 10^{-5}M[/tex]
