Respuesta :
Answer:
Option B is correct.
(5, -4)
Step-by-step explanation:
Given the system of equations:
[tex]4x+y = 16[/tex] ......[1]
[tex]2x+3y = -2[/tex] .....[2]
Multiply equation [2] by 2 both sides we have;
[tex]4x+6y = -4[/tex] .....[3]
Subtract equation [3] from [1] we have;
[tex]4x+y-4x-6y= 16+4[/tex]
Combine like terms;
[tex]-5y = 20[/tex]
Divide both sides by -5 we have;
y = -4
Substitute this value y in [1] we have;
4x+(-4) = 16
⇒4x - 4 = 16
Add 4 to both sides we have;
4x = 20
Divide both sides by 4 we have;
x = 5
therefore, the solutions of the given systems is, (5, -4).
