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The table below shows data from a survey about the amount of time high school students spent reading and the amount of time spent watching videos each week (without reading): Reading Video 5 1 5 4 7 7 7 10 7 12 12 15 12 15 12 18 14 21 15 26 Which response best describes outliers in these data sets?

A) Neither data set has suspected outliers.
B) The range of data is too small to identify outliers.
C) Video has a suspected outlier in the 26-hour value.
D) Due to the narrow range of reading compared to video, the video values of 18, 21, and 26 are all possible outliers.

Respuesta :

Answer with explanation:

Arranging the data in ascending order

1, 4,5,5,7,7,7,7, 10,12,12,12,12,14,15,15,15,18,21,26

There are 20 data values in data set.

Mean of data set

[tex]=\frac{\text{Sum of all the data values in the data set}}{\text{Total number of values}}\\\\=\frac{225}{20}\\\\=11.25[/tex]

Since there are , even number of data values in the data set,

So, Median

[tex]=\frac{(10th +11th) term}{2}\\\\=\frac{12+12}{2}=12[/tex]

First Quartile and third Quartile can be calculated directly ,using the concept of even and odd number of Observations in the data set.

[tex]Q_{1}=7, Q_{2}=15[/tex]

Mode> 12

Since data values is negatively skewed, Mean < Median <Mode.

To calculate Outlier

Interquartile Range (IQR)

 [tex]=Q_{3}-Q_{1}\\\\ =15-7\\\\=8[/tex]

Also, [tex]1. Q_{1}-1.5 *IQR\\\\=7-1.5 *8\\\\=-5\\\\2. Q_{3}+1.5 *IQR\\\\=15+1.5*8\\\\=15+12\\\\=27[/tex]

No, value exceeds 27, nor any value is less than -5.

So, there are no outliers in Data set, which has 20 values.

Option A:  Neither data set has suspected outliers.

Parrain

Based on the data given of the time spent by high school students reading and watching videos, we can say that A) Neither data set has suspected outliers.

What does the data tell us about outliers?

We can test for outliers by the formulas:

Lower range:

= Q₁ - 1.5 x Interquartile range

Upper range:
= Q₃ + 1.5 x Interquartile range

Interquartile range is:

= Q₃ - Q₁

= 15 - 7

= 8

Lower range is:

= 7 - 1.5 x 8

= -5

Upper range is:

= 15 + 1.5 x 8

= 27

No digits are higher than 27 and none are lower than -5 so there are no suspected outliers.

Find out more on outliers at https://brainly.com/question/2749543.

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