Respuesta :
NH₃ + H₂O ⇄ NH₄⁺ + OH⁻
pOH=-lg[OH⁻]
[OH⁻]=10^(-pOH)
[OH⁻]=10⁻⁴·⁶⁵=2.24×10⁻⁵ mol/L
pOH=-lg[OH⁻]
[OH⁻]=10^(-pOH)
[OH⁻]=10⁻⁴·⁶⁵=2.24×10⁻⁵ mol/L
Answer:
What is the hydronium ion concentration in a solution of HCl that has a pH of 4.65?
2.24 × 10n M
n = -5
What is the hydroxide ion concentration in a solution of NH3 with a pOH of 4.65?
2.24 × 10n M
n = -5
Explanation:
:D Hope this helps!
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