You drop a stone down a well that is 9.5 m deep. how long is it before you hear the splash? the 9) speed of sound in air is 343 m/s and air resistance is negligible.

1. stone

s=9,5m
a=g≈10m/s²

t1=?

s=(at²)/2
2s=at²
2s/a=t²
t=√(2s/a)=√(2*9.5m/10m/s²)=√(1,9s²)≈1,38s

2. sound

s=9,5m
V=343m/s²

t2=?

V=s/t
Vt=s
t=s/V=9,5m/343m/s≈0,03s

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V1+V2=1,38s+0,03s=1,41s

"Non nobis Domine, non nobis, sed Nomini tuo da gloriam."

Regards M.Y.

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EmranUllah EmranUllah · Answer 2 · 2020-02-01T21:15:13+01:00

Answer:

We have the following data provided to us, as we have:

Depth of the well, s=9.5 m,

Acceleration,a due to gravity,g= 9.8 m/sec²,
speed of sound,v=343 m/sec.

Explanation:

First part of the problem:

We have the following equations in order to solve the given problem:

s=(a×t²)/2,

Rearranging all the factors in the equations we get:

t=√(2×s/a),

so,

t=0.4 sec, ⇒Answer no.01

2. Sound.

s=9.5 meters,

V=343 m/sec²,
t₂=?,
V=s/t,
s=V×t,
t=s/V,
t=9.5/343,
t=0.027 seconds.⇒Answer no.2

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V1+V2=1,38s+0,03s=1,41s