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A fireworks company has two types of rockets called Zinger 1 and Zinger 2. The polynomial -16t2 + 150t gives the height in feet of Zinger 1 at t seconds after launch. The polynomial -16t2 + 165t gives the height of Zinger 2 at t seconds after launch. If the rockets are launched at the same time and both explode 6 seconds after launch, how much higher is Zinger 2 than Zinger 1 when they explode?

Respuesta :

musiclover10045

Zinger 1 = -16(6)^2 +150(6) = 324 feet

Zinger 2 = -16(6)^2 + 165(6) = 414 feet

414-324 = 90 feet

Zinger 2 is 90 feet higher

When they explode, Zinger 2 will be higher than Zinger 1 by; 90 ft

We are given the following polynomials to represent the height of both rockets as;

For Zinger 1; h(t) = -16t² + 150t

For Zinger 2; h(t) -16t² + 165t

We are told that the rockets are launched at the same time. Thus, after 6 seconds;

For Zinger 1; h(6) = -16(6²) + 150(6)

h(6) = -576 + 900

h(6) = 324 ft

For Zinger 2; h(6) = -16(6²) + 165(6)

h(6) = -576 + 990

h(6) = 414 ft

Thus, Zinger 2 is higher by;

414 - 324 = 90 ft

Read more at; https://brainly.com/question/4619288

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