Respuesta :
We may apply a mass balance here. The total moles of NaCl will remain constant before and after the mixing of the solutions. We have three solutions:
1) 25 ml of 5 M NaCl
2) 100 ml of 0 M NaCl
3) A mixture of these solutions with volume 125 ml and concentration C
The moles of a substance are equal to the product of the concentration and volume. Thus:
25 * 5 + 100 * 0 = 125 * C
C = 1 M
The concentration of the final solution is 1 M.
1) 25 ml of 5 M NaCl
2) 100 ml of 0 M NaCl
3) A mixture of these solutions with volume 125 ml and concentration C
The moles of a substance are equal to the product of the concentration and volume. Thus:
25 * 5 + 100 * 0 = 125 * C
C = 1 M
The concentration of the final solution is 1 M.
Answer:
Concentration is 1 mole/liter
Explanation:
Step 1: Determine the total number of moles of NaCl
[tex]molarity = \frac{moles}{volume}[/tex]
[tex]5.0 moles/liter = \frac{moles}{0.025 liter}[/tex]
[tex]moles = 0.125 moles[/tex]
Step 2: Determine the total volume
[tex]Volume_{total} =Volume_{water}+Volume_{solution} [/tex]
[tex]Volume_{total} =0.1+0.025 [/tex]
[tex]Volume_{total} =0.125 liter[/tex]
Step 3: Determine molarity
[tex]molarity = \frac{moles}{volume}[/tex]
[tex]molarity = \frac{0.125}{0.125}[/tex]
[tex]molarity = 1 mole/liter[/tex]