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A Gran plot for a potentiometric titration resulted in a slope of 5.56 x 105. Measurements were made using SCE as the reference electrode and the analyte Eo was determined to be 0.354 V. How many electrons are involved in the analyte oxidation/reduction?

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MasterElodin
We are given
s = 5.56 x 10^5
Eo = 0.354 V

We are asked how many electrons were involved in the redox reaction.

We use the Nernst Equation
Eo = s log [H+]
Subsituting
0.354 = 5.56 x 10^5 log [H+]
[H+] = 1 mole/L

Assuming that we have a 1 L volume, we have 1 mole of H+ that participates in the reaction which means there is also 1 mole of electron that is involved in the reaction.

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