Since we are given that the rate of growth of the bacteria is 4% then, the amount of bacteria is 1.04 times that of the amount the previous day. This can be mathematically expressed as,
A(t) = (Ao) x (1.04)^(t/n)
where A(t) is the amount after t days, Ao is the original amount, t is the number of days and n is the basis of the rate reported.
Substituting the known values,
A(t) = 5000 x (1.04)^(10/1)
A(t) = 7401.22
Thus, the amount of bacteria after 10 days is approximately equal to 7401.
