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A rectangle has a length of the fifth root of 16 inches and a width of 2 to the 1 over 5 power inches. Find the area of the rectangle. 2 to the 3 over 5 power inches squared 2 to the 4 over 5 power inches squared 2 inches squared 2 to the 2 over 5 power inches squared Points earned on this question: 0 Question 5 (Worth 2 points)

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Banabanana
[tex]A=length *width \\ \\A= \sqrt[5]{16}*2^{ \frac{1}{5}} =\sqrt[5]{2^4}*2^{ \frac{1}{5}} =2^{ \frac{4}{5}}*2^{ \frac{1}{5}}=2^{ \frac{4}{5} + \frac{1}{5}}=2^{ \frac{5}{5}}=2^1=2 \ in^2[/tex]
elemental

Answer: If you guys need verifacation, the answer above is correct. I know thins because i took the test with this answer and I got it right.


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