Respuesta :
Because we know the area in terms of paint flow, and paint flow in terms of time, we can substitute p(t) for p in the A(p) equation.
A(p(t)) = A(t) = π * (5t)^2 (assuming it's squared for the A(p).
B: 314 units^2
If A(p) = πp2 (instead of p^2), then A(t) = 10πt
B: 31.4 units^2
A(p(t)) = A(t) = π * (5t)^2 (assuming it's squared for the A(p).
B: 314 units^2
If A(p) = πp2 (instead of p^2), then A(t) = 10πt
B: 31.4 units^2
Answer:
A). A[p(t)] = 25πt²
B). 314 square unit
Step-by-step explanation:
A bucket of paint on a tile floor. The paint flow can be expressed with the function p(t) = 5t
where t represents the time and p represents how far the paint will flow.
Area of the pattern can be expressed as A(p) = πp²
A). Area of the circle of spilled paint can be defined as A[p(t)] = π(5t)²
A[p(t)] = 25πt²
B). In this part we have to calculate the area of spilled paint after 2 minutes.
A[p{2)] = 25π(2)²
= 100π
= 100(3.14)
= 314 square unit
