Answer:
[tex]a+b\geq 30\\b-a\geq 10\\b>a[/tex]
Step-by-step explanation:
Givens
- The sum of two positive integers is at least 30.
- Their difference is at least 10.
- b is greater than a.
With this information, we can find a system of inequalities. Remember that "at least" means that the sum of these number is 30 or more, and their difference is 10 or more. So
[tex]a+b\geq 30\\b-a\geq 10\\b>a[/tex]
The solution of this system is attached. Remember that the solution of a system of inequalities is a graphic solutions, the intersection of all three areas is the solution.
However, the problem is just asking for the system that could represent this situation. So, the answer is
[tex]a+b\geq 30\\b-a\geq 10\\b>a[/tex]
