Respuesta :
Na₂CO₃ → 2Na⁺ + CO₃²⁻
CO₃²⁻ + H₂O ⇄ HCO₃⁻ + OH⁻
HCO₃⁻ + H₂O ⇄ CO₂·H₂O + OH⁻
Na⁺, CO₃²⁻, HCO₃⁻, OH⁻
CO₃²⁻ + H₂O ⇄ HCO₃⁻ + OH⁻
HCO₃⁻ + H₂O ⇄ CO₂·H₂O + OH⁻
Na⁺, CO₃²⁻, HCO₃⁻, OH⁻
Answer : The ions present in a solution of [tex]Na_2CO_3[/tex] are, [tex]Na^+,CO_3^{2-}[/tex]
Explanation :
As we know that in an aqueous solution, the compound is dissociated into ions.
The given compound is, [tex]Na_2CO_3[/tex].
When [tex]Na_2CO_3[/tex] is dissolved in an aqueous solution then it dissociates into sodium ion [tex](Na^+)[/tex] and carbonate ion [tex](CO_3^{2-})[/tex].
The balanced chemical reaction will be :
[tex]Na_2CO_3(aq)\rightarrow 2Na^+(aq)+CO_3^{2-}(aq)[/tex]
Hence, the ions present in a solution of [tex]Na_2CO_3[/tex] are, [tex]Na^+,CO_3^{2-}[/tex]
