y - 3 = -(x + 1)
y - 3 = -x - 1
y = -x - 1 + 3
y = -x + 2....slope here is -1. A parallel line will have the same slope
y = mx + b
slope(m) = -1
(4,2)...x = 4 and y = 2
sub and find b, the y int
2 = -1(4) + b
2 = -4 + b
2 + 4 = b
6 = b
ur parallel line is : y = -x + 6
or
y - y1 = m(x - x1)
slope(m) = -1
(4,2)...x1 = 4 and y1 = 2
sub
y - 2 = -1(x - 4)
they are both correct
