Respuesta :

mergl
(8.08x10^24 H atoms)(3 C atoms/8 H atoms)
=3.03x10^24 C atoms
3.03x10^24+8.08x10^24=1.111x10^25 atoms total
(1.111x10^25)/(6.02x10^23)=18.4551495 mol C3H8
18.4551495(44.01)=812.2111296g C3H8

Answer:

[tex]3.03\times 10^{24} atoms[/tex] of carbon in the sample.

73.7960 grams is the total mass of the sample.

Explanation:

Compound = [tex]C_3H_8[/tex]

Total numbers of hydrogen atoms in a compound = [tex]8.08\times 10^{24}[/tex] atoms

In one molecule of compound there are 8 hydrogen atoms.

Then x number of molecules of compound having [tex]8.08\times 10^{24}[/tex] hydrogen atoms.

[tex]x=\frac{8.08\times 10^{24}}{8} molecules=1.01\times 10^{24} molecules[/tex]

In one molecule of compound there are 3 carbon atoms.

Then [tex]1.01\times 10^{24} molecules[/tex] of given compound will have :

[tex]3\times 1.01\times 10^{24} atoms=3.03\times 10^{24} atoms[/tex] of carbon

[tex]3.03\times 10^{24} atoms[/tex] of carbon in the sample.

Moles of given compounds = n

[tex]x=N_A\times n[/tex]

[tex]n=\frac{N_A}{x}=\frac{1.01\times 10^{24}}{6.022\times 10^{23} mol^{-1}}[/tex]

n = 1.6771 moles

Mass of 1.6771 moles of given compound:

[tex]1.6771 mo\times (3\times 12 g/mol+8\times 1 g/mol)=73.7960 g[/tex]

73.7960 grams is the total mass of the sample.