Respuesta :
(8.08x10^24 H atoms)(3 C atoms/8 H atoms)
=3.03x10^24 C atoms
3.03x10^24+8.08x10^24=1.111x10^25 atoms total
(1.111x10^25)/(6.02x10^23)=18.4551495 mol C3H8
18.4551495(44.01)=812.2111296g C3H8
=3.03x10^24 C atoms
3.03x10^24+8.08x10^24=1.111x10^25 atoms total
(1.111x10^25)/(6.02x10^23)=18.4551495 mol C3H8
18.4551495(44.01)=812.2111296g C3H8
Answer:
[tex]3.03\times 10^{24} atoms[/tex] of carbon in the sample.
73.7960 grams is the total mass of the sample.
Explanation:
Compound = [tex]C_3H_8[/tex]
Total numbers of hydrogen atoms in a compound = [tex]8.08\times 10^{24}[/tex] atoms
In one molecule of compound there are 8 hydrogen atoms.
Then x number of molecules of compound having [tex]8.08\times 10^{24}[/tex] hydrogen atoms.
[tex]x=\frac{8.08\times 10^{24}}{8} molecules=1.01\times 10^{24} molecules[/tex]
In one molecule of compound there are 3 carbon atoms.
Then [tex]1.01\times 10^{24} molecules[/tex] of given compound will have :
[tex]3\times 1.01\times 10^{24} atoms=3.03\times 10^{24} atoms[/tex] of carbon
[tex]3.03\times 10^{24} atoms[/tex] of carbon in the sample.
Moles of given compounds = n
[tex]x=N_A\times n[/tex]
[tex]n=\frac{N_A}{x}=\frac{1.01\times 10^{24}}{6.022\times 10^{23} mol^{-1}}[/tex]
n = 1.6771 moles
Mass of 1.6771 moles of given compound:
[tex]1.6771 mo\times (3\times 12 g/mol+8\times 1 g/mol)=73.7960 g[/tex]
73.7960 grams is the total mass of the sample.