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A train is moving at a constant speed on a surface inclined upward at 15.0° with the horizontal and travels 300 meters in 5 seconds. Calculate the horizontal velocity of the train at the end of 3 seconds.

Respuesta :

he speed up the incline is 300m/5s = 60m/s

the horizontal component of that is 60 cos 15 = 57.95m/s

he speed up the incline is 300m/5s = 60m/s


the horizontal component of that is 60 cos 15 = 57.95m/s


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