What is the range of y=log8x, ? all real numbers less than 0 all real numbers greater than 0 all real numbers not equal to 0 all real numbers

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JeanaShupp JeanaShupp · Answer 1 · 2018-10-31T07:44:24+01:00

Answer: The range of y= log 8x is all real values .

Step-by-step explanation:

Range is the set of all defined values of y correspond to the domain.

The given function y= log 8 x = log 8+log x=

where domain of log x= {x∈R|x>0} =(0,∞) , all positive real values.

and Range={y|y∈R}=(-∞,∞) i.e.all real values.

Therefore range of y=log8x would be same as of logx such that

Range of y={y|y∈R}=(-∞,∞) i.e.all real values.

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aksnkj aksnkj · Answer 2 · 2022-02-14T09:48:00+01:00

To find the range we will solve by using the log rule. The range of y= log 8x is for all real values.

Given:

y=log8x

According to the questions it is required to find the range of the function.

The range is a set of all the defined values of y-correspond to the domain.

Now by applying log rule we get

[tex]\rm y= log 8 x \\\\y= log 8+log x[/tex]

Where we know the domain of log x= {x∈R|[tex]x>0} =[/tex](0,∞)

all the positive real values.

Domain = {x∈R|x[tex]>0}[/tex]} =(0,∞)

Range = {y|y∈R}=(-∞,∞)

i.e.all real values.

Therefore, Range of y={y|y∈R}=(-∞,∞) i.e.all real values.

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