The area of the regular octagon is approximately 54 cm2.What is the length of line segment AB, rounded to the nearest tenth?

3.4 cm
4.8 cm
24 cm
27 cm

The area of the regular octagon is approximately 54 cm2What is the length of line segment AB rounded to the nearest tenth 34 cm 48 cm 24 cm 27 cm class=

Respuesta :

The length of line segment AB is 3.4cm.
The area of octagon is given as 2a^2(1+sqrt{2})
Where a is the side of octagaon. All sides of octagon are same.
As, 2a^2(1+sqrt{2}) = 54cm
Then, a^2 = 54/2(1+sqrt{2})
a^2 = 54/4.828
a^2 = 11.19
a = 3.4 cm

The length of line segment AB, rounded to the nearest tenth is 3.4 cm.

What is a regular octagon?

Octagon, in geometry, is a polygon with eight sides, with eight interior angles and eight exterior angles, so a regular octagon has all sides the same size and all angles the same measure.

knowing the area of octagon is given as [tex]2a^2(1+\sqrt{2})[/tex], we can find that:

[tex]2a^2(1+\sqrt{2}) = 54cm\\a^2 = 54/2(1+\sqrt{2})\\a^2 = 54/4.828\\a^2 = 11.19\\a = 3.4 cm[/tex]

See more about regular octagon at brainly.com/question/10024737