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For a project, Gabrielle made a model of an Egyptian pyramid. The square base has a side length measuring 10 inches. The pyramid is 12 inches tall. What is the surface area of the model? square inches

Respuesta :

merlynthewhizz
The pyramid is shown in the diagram below.
The pyramid is built from four congruent triangles and one square as the base

We have the side of the square, so the area is = 10×10 = 100

We need the height of the triangle to work out its area. We can find out by using the height of the pyramid and half of the length of the side of the square.

Using the Pythagoras rule
Height of triangle = [tex] \sqrt{12^{2}+ 5^{2} } =13[/tex]

Area of one triangle = 1/2×10×12=60
Surface area of the pyramid = 100 + (4×60) = 340 square inches
Ver imagen merlynthewhizz
ogorwyne

From the project that Gabrielle is making, the surface area of this model has been calculated to be 360 square inches.

How to solve for the surface area of the shape

First we have to find the height of the slope

[tex]\sqrt{(10/2^2+12^2)}[/tex]

= 13

S1 = 10² = 100

s2 = 4 x 1/2 x 10 x 13

= 260 square inches

Surface area =  S1 + S2

= 100 + 260

= 360 square inches

From the calculation above, the surface area of the pyramid that Gabrielle is making is  360 square inches.

Read more on surface area here: https://brainly.com/question/16519513

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