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The point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is y + 7 = (x – 10). What is the standard form of the equation for this line?

A. 2x – 5y = –15
B. 2x – 5y = –17
C. 2x + 5y = –15
D. 2x + 5y = –17

Respuesta :

2x-5y=-17 or b of course

The point slope form of the line which passes through the points [tex](-5,-1)[/tex] and [tex](10,-7)[/tex] is [tex]\fbox{\begin\\\ \math 2x+5y=-15\\\end{minispace}}[/tex] i.e., [tex]\fbox{\begin\\\ \bf option C\\\end{minispace}}[/tex].

Further explanation:

It is given that line passes through the points [tex](-5,-1)[/tex] and [tex](10,-7)[/tex].

The objective is to determine the point slope form of the line which passes through the points [tex](-5,-1)[/tex] and [tex](10,-7)[/tex].

The options given are as follows:

Option A: 2x-5y=-15

Option B: 2x-5y=-17

Option C: 2x+5y=-15

Option D: 2x+5y=-17

Consider the point [tex](-5,-1)[/tex] as [tex](x_{1},y_{1})[/tex] and [tex](10,-7)[/tex] as [tex](x_{2},y_{2})[/tex].

Slope of a curve is defined as the change in the value of [tex]y[/tex] with respect to change in value of [tex]x[/tex].

The slope of the line is calculated as follows:

[tex]\fbox{\begin\\\ \math m=\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\end{minispace}}[/tex]

To obtain the value of slope substitute the value of [tex]x_{1},y_{1},x_{2},y_{2}[/tex] in the above equation.

[tex]\begin{aligned}m&=\dfrac{-7-(-1)}{10-(-5)}\\&=\dfrac{-6}{15}\\&=\dfrac{-2}{5}\end{aligned}[/tex]

Therefore, the slope of the line is [tex]\fbox{\begin\\\ \math m=\dfrac{-2}{5}\\\end{minispace}}[/tex]

The general way to express the equation of a line in its point slope form is as follows:

[tex]\fbox{\begin\\\ \math (y-y_{1})=m(x-x_{1})\\\end{minispace}}[/tex]

To obtain the point slope form of the equation of the line substitute the value of [tex]m[/tex], [tex]x_{1}[/tex] and [tex]y_{1}[/tex] in the above equation.

[tex]\begin{aligned}(y-(-1))&=\dfrac{-2}{5}(x-(-5))\\(y+1)&=\dfrac{-2}{5}(x+5)\\5y+5&=-2x-10\\5y+2x&=-15\end{aligned}[/tex]

From the above calculation it is concluded that the point slope form the equation of a line is [tex]\fbox{\begin\\\ \math 5y+2x=-15\\\end{minispace}}[/tex]

Figure 1 (attached in the end) represents the graph of the function [tex]5y+2x=-15[/tex].

This implies that the correct option for the point slope form of the line is option C.

Therefore, the point slope form of the line which passes through the points [tex](-5,-1)[/tex] and [tex](10,-7)[/tex] is [tex]2x+5y=-15[/tex] i.e., option C.

Learn more:

1. A problem to complete the square of quadratic function https://brainly.com/question/12992613  

2. A problem to determine the slope intercept form of a line https://brainly.com/question/1473992

3. Inverse function https://brainly.com/question/1632445.

Answer details

Grade: High school

Subject: Mathematics

Chapter: Linear equation

Keywords: Equation, linear equation, slope, intercept, x-intercept, y-intercept, intersect, graph, curve, slope intercept form, line, y=3x/2-3, standard form, point slope form.  

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