12.The diameter of a basketball rim is 18 inches. A standard basketball has a circumference of 30 inches. About how much room is there between the ball and the rim in a shot in which the ball goes in exactly in the center of the rim? Show your work.

Respuesta :

In order to solve this equation, you need to find the diameter of the basketball, find the radius of both the rim and the basketball, and then subtract the rim by the ball to find the distance.

1) Finding diameter of basketball.
 
    The formula for circumference is C=(3.14)D.
    You know C (which is 30) so you have to solve for D.
    
    30 = (3.14)D
   /3.14    /3.14
 9.55 = D
   
 *Note that the diameter of the circle has been rounded, so has pi*

2) Finding the two radius.
    The formula for this is D = 2R
    Solve for each.
   
    Ball:
    D = 2R
9.55 = 2R
  /2       /2
4.775 = R
*rounded to 4.8*
   
   Rim:
  D = 2R
18 = 2R
/2      /2
  9 = R

3) now subtract the rim by the ball to find the distance.
    
    9 - 4.8 = 4.2

    Therefore, there is 4.2 inches between the ball and the rim.
   
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1. Diameter of Basketball:

circumference = 3.14 * d

30 = 3.14 * d

(divide 3.14 from both sides of the equal sign to leave "d" by itself)  

30/3.14 = d

9.55 ≈ d (rounded)

2. Radius for the Basketball & Rim

Basketball:

diameter = 2 * r

9.55 = 2 * r

9.55/2 = r

4.775 = r  (round 4.8)

Rim:

diameter = 2 * r

18 = 2 * r

18/2 = r

9 = r

3. Subtract

9 - 4.8 = 4.2 in