If the partial pressure of the diatomic gas is 0.630 ATM what is the total pressure?
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Answer:
2.944 ATM
Explanation:
There are 14 molecules of gas mixture: 5 molecules of orange gas, 6 of blue gas and 3 of green gas. The green gas is the diatomic gas because it's formed by two atoms. The blue and the orange are monoatomic gases.
By the Dalton's Law, the partial pressure of a gas in a mixture of gas, may be calculeted knowing its molar fraction (Xi):
[tex]Xi = \frac{molecules of the gas}{total molecules of the mixture} \\\\Xi = \frac{3}{14} \\\\Xi = 0.214[/tex]
Dalton's Law: Pi = Xi x Pt
0.630 = 0.214xPt
Pt = 2.944 ATM
Obs: The number of significant algorism such be the same of all parcels of the equation, including the result.
The total pressure of the model given in the question is 2.944 atm
A diatomic gas is a gas made up of two or more atoms of the gas.
Considering the diagram given above, we can see that the green balls represents the diatomic gas as it contains 2 ball per molecule.
Now, we shall determine the mole fraction of the diatomic gas.
Mole of diatomic gas = 3 balls
Total mole = 3 green balls + 6 blue balls + 5 orange balls
Total mole = 14 balls
Mole fraction of diatomic gas =?
[tex]Mole fraction = \frac{mole}{total mole }\\\\ = \frac{3}{14}\\\\[/tex]
Mole fraction of diatomic gas = 0.214
Finally, we shall determine the total pressure.
Partial pressure of diatomic gas = 0.630 atm
Mole fraction of diatomic gas = 0.214
Total pressure = Partial pressure / mole fraction
Total pressure = 0.630 / 0.214
Thus, the total pressure is 2.944 atm
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