Which statement proves that △XYZ is an isosceles right triangle?

XZ ⊥ XY
XZ = XY = 5
The slope of XZ is , the slope of XY is , and XZ = XY = 5.
The slope of XZ is , the slope of XY is , and the slope of ZY = 7.

Which statement proves that XYZ is an isosceles right triangle XZ XY XZ XY 5 The slope of XZ is the slope of XY is and XZ XY 5 The slope of XZ is the slope of X class=

Respuesta :

The second statement does lol

Answer:

XZ = XY = 5 units  are equal .

ΔXYZ is a Right isosceles triangle .

Step-by-step explanation:

As to an triangle is isosceles triangles the two sides of the triangle must be equal .

Formula

[tex]Distance\ formula = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}[/tex]

As the vertices of the ΔXYZ be X (1,3) , Y (4,-1) and Z(5,6) .

[tex]XY = \sqrt{(4-1)^{2}+(-1-3)^{2}}[/tex]

[tex]XY = \sqrt{(3)^{2}+(-4)^{2}}[/tex]

[tex]XY = \sqrt{9+16}[/tex]

[tex]XY = \sqrt{25}[/tex]

[tex]\sqrt{25}= 5[/tex]

[tex]XY = 5\ units[/tex]

[tex]YZ = \sqrt{(5-4)^{2}+(6-(-1))^{2}}[/tex]

[tex]YZ = \sqrt{(1)^{2}+(7)^{2}}[/tex]

[tex]YZ = \sqrt{1+49}[/tex]

[tex]YZ = \sqrt{50}\ units[/tex]

[tex]ZX = \sqrt{(1-5)^{2}+(3-6)^{2}}[/tex]

[tex]ZX = \sqrt{(-4)^{2}+(-3)^{2}}[/tex]

[tex]ZX = \sqrt{16+9}[/tex]

[tex]ZX = \sqrt{25}[/tex]

[tex]\sqrt{25}= 5[/tex]

ZX = 5 units

Thus XZ = XY = 5 units  are equal .

Therefore ΔXYZ is a Right isosceles triangle .