we have
[tex]\sqrt{\frac{55x^{7}y^{6}}{11x^{11}y^{8}}}[/tex]
we know that
[tex]\sqrt{\frac{55x^{7}y^{6}}{11x^{11}y^{8}}} =\sqrt{\frac{55}{11}\frac{x^{7}}{x^{11}}\frac{y^{6}}{y^{8}}} \\ \\= \sqrt{\frac{5}{x^{4} y^{2}}} \\ \\ =\frac{\sqrt{5}}{x^{2} y}[/tex]
therefore
the answer is
The expression equivalent is [tex]\frac{\sqrt{5}}{x^{2} y}[/tex]
