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Boyle’s law states that when considering gases, volume varies inversely with pressure. If V represents the volume of the gas and P represents the pressure of the gas, what would the formula be that represents this relationship? If a balloon has a volume of 4 L of gas with a pressure of 5 atmospheres, what will the volume be when the pressure is 3 atmospheres?

Respuesta :

mergl
(P1*V1)=(P2*V2)
P1= 5 atm
P2= 3 atm
V1= 4L
V2=?
(5*4)=(3*V2)
20=3(V2)
V2=20/3 L which is 6.66666667L
boffeemadrid

The formula and volume of gas at a certain pressure is required.

The formula is [tex]\dfrac{P_1}{P_2}=\dfrac{V_2}{V_1}[/tex]

The volume is 6.67 L.

From Boyle's law the required expression is

[tex]P\propto\dfrac{1}{V}[/tex]

[tex]P_1[/tex] = Initial pressure = 5 atm

[tex]V_1[/tex] = Initial volume = 4 L

[tex]P_2[/tex] = Final pressure = 3 atm

[tex]V_2[/tex] = Final volume

The formula would be

[tex]\dfrac{P_1}{P_2}=\dfrac{V_2}{V_1}\\\Rightarrow V_2=\dfrac{P_1}{P_2}\times V_1\\\Rightarrow V_2=\dfrac{5}{3}\times 4\\\Rightarrow V_2=6.67\ \text{L}[/tex]

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https://brainly.com/question/1437490?referrer=searchResults

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