Find the value of the discriminant describe the number and type of roots for the equation. Then find the exact solution of the following quadratic equation by using the Quadratic Formula.
x2 - 6x + 25 = 0
a.
The discriminant is -64, so there are 2 complex roots.

x = 1103-05-05-00-00_v2_files/i0050000.jpg
c.
The discriminant is 34, so there are 2 real and rational roots.

x = 1103-05-05-00-00_v2_files/i0050001.jpg
b.
The discriminant is -64, so there are 2 complex roots

x = 1103-05-05-00-00_v2_files/i0050002.jpg
d.
The discriminant is -34, so there are 2 complex roots

x = 1103-05-05-00-00_v2_files/i0050003.jpg

Respuesta :

hello : 
x² - 6x + 25 = 0
The discriminant is : b²-4ac         a =1     b = - 6    c =25
(-6)²-4(1)(25) =36-100 = -64
The discriminant is -64, so there are 2 complex roots

The  discriminant is -64 and the two complex roots are 3 +4i and 3 - 4i

Given the quadratic equation [tex]x^2 - 6x + 25 = 0[/tex]

  • Discriminant D = b² - 4ac

From the equation, a = 1, b = -6 and c = 25

Substitute into the formula:

D = (-6)² - 4(1)(25)

D = 36 - 100

D = -64

Get the solution using the general formula expressed as:

[tex]x=\frac{-b\ \pm \sqrt{D} }{2a} \\x=\frac{-(-6)\ \pm \sqrt{-64} }{2(1)} \\x=\frac{6\ \pm 8i }{2} \\x=3 \pm4i\\x=3+4i \ and \ 3 - 4i[/tex]

Hence the  discriminant is -64 and the two complex roots are 3 +4i and 3 - 4i

Learn more about discriminants here; https://brainly.com/question/15270619?source=archive