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x² - 6x + 25 = 0
The discriminant is : b²-4ac a =1 b = - 6 c =25
(-6)²-4(1)(25) =36-100 = -64
The discriminant is -64, so there are 2 complex roots
x² - 6x + 25 = 0
The discriminant is : b²-4ac a =1 b = - 6 c =25
(-6)²-4(1)(25) =36-100 = -64
The discriminant is -64, so there are 2 complex roots
The discriminant is -64 and the two complex roots are 3 +4i and 3 - 4i
Given the quadratic equation [tex]x^2 - 6x + 25 = 0[/tex]
- Discriminant D = b² - 4ac
From the equation, a = 1, b = -6 and c = 25
Substitute into the formula:
D = (-6)² - 4(1)(25)
D = 36 - 100
D = -64
Get the solution using the general formula expressed as:
[tex]x=\frac{-b\ \pm \sqrt{D} }{2a} \\x=\frac{-(-6)\ \pm \sqrt{-64} }{2(1)} \\x=\frac{6\ \pm 8i }{2} \\x=3 \pm4i\\x=3+4i \ and \ 3 - 4i[/tex]
Hence the discriminant is -64 and the two complex roots are 3 +4i and 3 - 4i
Learn more about discriminants here; https://brainly.com/question/15270619?source=archive