Respuesta :
Answer:
In 0.1 M [tex](NH_{4})_{2}S[/tex] solution, [tex]CaSO_{4}[/tex] will be most soluble
Explanation:
Dissociation equilibrium of [tex]CaSO_{4}[/tex] :
[tex]CaSO_{4}\rightleftharpoons Ca^{2+}+SO_{4}^{2-}[/tex]
According to Le-chatliers principle, addition of either [tex]Ca^{2+}[/tex] or [tex]SO_{4}^{2-}[/tex] ions into solution of [tex]CaSO_{4}[/tex] leads to shifting in dissociation equilibrium toward left. Therefore solubility of [tex]CaSO_{4}[/tex] decreases.
According to Le-chatliers principle, removal of either [tex]Ca^{2+}[/tex] or [tex]SO_{4}^{2-}[/tex] ions into solution of [tex]CaSO_{4}[/tex] leads to shifting in dissociation equilibrium toward right. Therefore solubility of [tex]CaSO_{4}[/tex] increases.
[tex]Ca^{2+}[/tex] gets removed from solution by forming sparingly soluble salt CaS upon addition of [tex](NH_{4})_{2}S[/tex] solution.
So solubility of [tex]CaSO_{4}[/tex] increases upon addition of [tex](NH_{4})_{2}S[/tex] solution