Respuesta :
M(CH₂Br)=12.0+2*1.0+79.9=93.9 g/mol
M=188 g/mol
N=M/M(CH₂Br)
N=188/93.9=2
C₂H₄Br₂
M=188 g/mol
N=M/M(CH₂Br)
N=188/93.9=2
C₂H₄Br₂
Answer : The molecular of the compound is, [tex]C_2H_4Br_2[/tex]
Explanation :
The Empirical formula = [tex]CH_2Br[/tex]
The empirical formula weight = 1(12) + 2(1) + 1(80) = 94 gram/eq
Now we have to calculate the molecular formula of the compound.
Formula used :
[tex]n=\frac{\text{Molecular formula}}{\text{Empirical formula weight}}[/tex]
where,
n = valency factor
Now put all the given values in this formula, we get:
[tex]n=\frac{188}{94}=2[/tex]
Molecular formula = [tex](CH_2Br)_n=(CH_2Br)_2=C_2H_4Br_2[/tex]
Therefore, the molecular of the compound is, [tex]C_2H_4Br_2[/tex]
