Respuesta :
[tex] f(x)=\dfrac{x}{x-2}\\
y=\dfrac{x}{x-2}\\
y(x-2)=x\\
xy-2y=x\\
xy-x=2y\\
x(y-1)=2y\\
x=\dfrac{2y}{y-1}\\\
f^{-1}(x)=\dfrac{2x}{x-1}[/tex]
Answer:
Step-by-step explanation:
Its the answer with -6 at the end. (D) for me.