Respuesta :

[tex] f(x)=\dfrac{x}{x-2}\\ y=\dfrac{x}{x-2}\\ y(x-2)=x\\ xy-2y=x\\ xy-x=2y\\ x(y-1)=2y\\ x=\dfrac{2y}{y-1}\\\ f^{-1}(x)=\dfrac{2x}{x-1}[/tex]

Answer:

Step-by-step explanation:

Its the answer with -6 at the end. (D) for me.